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Bryan Rasmussen
I believe this should solve your problem, if I've understood it.
<xsl:template match="tag1 | tag3 | tag4">
<xsl:copy><xsl:copy-of select="@*"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="tag2">
<i><xsl:apply-templates/></i>
</xsl:template>
always assuming that you have not defined a template for text()
and assuming that you don't have any requirements for doing stuff that can't be
done, like copying cdata as is.
also assuming that there is not requirement to keep whitespace as is in the
original content.
Quoting "Bradley, Peter" <PBradley(_at_)uwic(_dot_)ac(_dot_)uk>:
It pays to be honest, so I'll be up-front about this. The question arises
from an assignment on a course I'm doing.
However, I don't want to cheat, so I'll try to form the question in the most
general way that I can:
The purpose of the exercise is to convert some xml to html. I have a
repeating element under the root - let's call it anElement. Initially, the
requirement was to output all its contents, unchanged. So I could do this:
<xsl:for-each select="anElement">
<xsl:value-of select="." />
</xsl:for-each>
The anElement element has mixed content and would be described in a DTD as
follows:
<!ELEMENT anElement (#PCDATA | tag1 | tag2 | tag3 | tag4)* >
All the child tags contain #PCDATA only.
The new requirement is to print all the content as before, but to print the
contents of tag2 (say) in italics - i.e. surround its contents with <i></i>
html tags.
I've sweated over this all weekend and can't work out how to solve it. If I
treat each tag individually in a for-each or an apply-templates/template
combination (if that makes sense), I can't see how to output the #PCDATA in
anElement.
Any help would be appreciated - especially a pointer to a resource that will
let me work it out for myself. I've tried the obvious places like w3c
schools.
Thank for your attention
Peter
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