I have a xsl file and a xml file. The xml contains 2
RSS feed URLs. I use the xsl file to transform the RSS
feed into HTML which lists the items of the feed. But
I got an error message:
"The XML page cannot be displayed
Cannot view XML input using XSL style sheet. Please
correct the error and then click the Refresh button,
or try again later.
--------------------------------------------------------------------------------
Access is denied. Error processing resource
'file://Users/zjwsun/Sites/hrl/xsl/getRSS.xsl'. "
I don't know what is wrong. Thanks for any help.
Here's the XML:
<?xml version="1.0"?>
<?xml-stylesheet
href="/Users/zjwsun/Sites/hrl/xsl/getRSS.xsl"
type="text/xsl"?>
<RSSChannels>
<RSSChannel
src="http://www.tinnitus-research.org/atr.xml"/>
<RSSChannel
src="http://www.medicinenet.com/rss/specialty/Tinnitus.xml"/>
</RSSChannels>
Here's the XSL:
<?xml version="1.0"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:dc="http://purl.org/dc/elements/1.1/";
version="1.0">
<xsl:output method="html" encoding="iso-8859-1"/>
<xsl:template match="RSSChannels">
<html>
<head>
<title>Today's Headlines</title>
</head>
<body>
<xsl:apply-templates/>
</body>
</html>
</xsl:template>
<xsl:template match="RSSChannel">
<xsl:apply-templates select="document(@src)"/>
</xsl:template>
<!-- Named template outputs HTML a element with href
link and RSS
description as title to show up in mouseOver
message. -->
<xsl:template name="a-element">
<xsl:element name="a">
<xsl:attribute name="href"><xsl:apply-templates
select="*[local-name()='link']"/></xsl:attribute>
<xsl:attribute name="title"><xsl:apply-templates
select="*[local-name()='description']"/></xsl:attribute>
<xsl:value-of select="*[local-name()='title']"/>
</xsl:element>
</xsl:template>
<!-- Output RSS channel name as HTML a link inside of
h1 element. -->
<xsl:template match="*[local-name()='channel']">
<xsl:call-template name="a-element"/>
<!-- Following line for RSS .091 -->
<xsl:apply-templates
select="*[local-name()='item']"/>
</xsl:template>
<!-- Output RSS item as HTML a link inside of p
element. -->
<xsl:template match="*[local-name()='item']">
<xsl:call-template name="a-element"/>
<xsl:text> </xsl:text>
<xsl:if test="dc:date">
<!-- Show date if available -->
<xsl:text>( </xsl:text>
<xsl:value-of select="dc:date"/>
<xsl:text>) </xsl:text>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
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