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RE: Summarising XML datasets

2004-12-21 02:42:08
Hi,

I've tried following the example from Jeni's site and come up with the
following:

snip

<xsl:template match="results">
    <xsl:for-each select="photograph[count(. | key('idkey', 
id)[1])=1]">
        <h3><xsl:value-of select="id" /></h3>
        <h4><xsl:value-of select="name"/></h4>
        <h5><xsl:value-of select="description"/></h5>
      <xsl:for-each select="key('subjectkey', id)">
            <TABLE border="0" width="75%">
                <tr>
                    <th width="10%" align="right">Subject</th>
                    <td width="90%" align="left"><xsl:value-of
select="subject" /></td>
                </tr>
            </TABLE>
            <hr width="75%" align="left"/>
         </xsl:for-each>
  
    </xsl:for-each>
</xsl:template>
</xsl:stylesheet>

This works unless I have a duplicate subject node, which actually can
happen.

I'm a little bit stuck with how to only display unique subjects.

Then you need to generate a second grouping key, which is a concatenation of ID 
and subject.

  <xsl:key name="subjectkey" match="photograph" use="concat(id, ' ', subject)"/>

and list subjects with

  <xsl:for-each select="key('idkey', id)[generate-id(.) = 
generate-id(key('subjectkey', concat(id, ' ', subject)))]">
    <xsl:if test="not(position() = 1)">, </xsl:if>
    <xsl:value-of select="subject" />
  </xsl:for-each>

Cheers,

Jarno

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