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RE: xsl:sort not working under unix???

2004-12-20 13:08:39
You've asked for a numeric sort on an alphabetic field, so the values are
converted to numbers and they all translate to NaN: therefore all the sort
key values are the same.

Michael Kay
http://www.saxonica.com/ 

-----Original Message-----
From: Sylvia Murphy [mailto:murphys(_at_)ucar(_dot_)edu] 
Sent: 20 December 2004 18:23
To: xsl mailing list
Subject: [xsl] xsl:sort not working under unix???

to demonstrate this behavior, I have created a simple test case.  Are 
there known unix issues or is the stupid newbie error. note the 
transformation is occuring in the browser (NN7).  


Thanks,

sylvia

simple xml file:

<?xml version="1.0"?>
<?xml-stylesheet type="text/xml" href="./sort.xsl"?>
<addressbook>
 <address>
   <name>Sylvia</name>
   <age>39</age>
   <state>CA</state>
 </address>

 <address>
   <name>Mariana</name>
   <age>90</age>
   <state>CO</state>
 </address>

</addressbook>


here is the style sheet:
<?xml version="1.0"?>

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

  <xsl:template match="/">
    <html>
    <head></head>
    <body>
    <h1> TEST of SORT</h1>


    <xsl:for-each select="addressbook">
      <xsl:sort select="name" data-type="number"/>
      <xsl:apply-templates/>
    </xsl:for-each>
    </body>
    </html>

  </xsl:template>

  <xsl:template match="address">
    <p>
    <xsl:value-of select="age"/>
    <xsl:text> </xsl:text>
    <xsl:value-of select="name"/>
    <xsl:value-of select="$newline"/>
    </p>
  </xsl:template>


</xsl:stylesheet>











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