When you use a node-set in a context where a boolean is expected, the answer
is false if the node-set is empty, true if it is non-empty.
In 2.0, see the rules for "effective boolean value".
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: António Mota [mailto:xptm(_at_)sapo(_dot_)pt]
Sent: 20 December 2004 17:06
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Comparing nodes in axis
Altought i have allready structures like this,
some-axis[true], i can?t quite
comprehend it.
In this case, how such statement should be translated to
plain english?
"Give me the ancestors that are menus of the current node if
the current node is
the same as the menu node at absolute position $pos"?
What i can't comprehend is the use of true/false. Suppose i
have a expression
that has no term of comparation to the current node. How such
a construct is
feasible?
Quoting Michael Kay <mike(_at_)saxonica(_dot_)com>:
Or you could do
xsl:variable name="P" select="(//menu)[$pos]"
xsl:if test="ancestor::menu[count(.|$P)=1]"
Michael Kay
http://www.saxonica.com/
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