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Re: Best way to count siblings

2004-12-15 03:04:24



  <xsl:value-of select="count(preceding-sibling::* | following-sibling::*)"/>

count(../*) -1 is shorter, you;d have to ask an implementer which is
more efficient. Often the siblings are the current node list in which
case last()-1 is likely to be the most efficient.

David

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