"Hardy" == Hardy Merrill
<HMerrill(_at_)dhcr(_dot_)state(_dot_)ny(_dot_)us> writes:
Hardy> but that's not working - I keep getting this error:
Hardy> msxml4.dll error '80004005'
Hardy> Keyword xsl:sort may not be used here.
Hardy> ------------------------------------
Hardy> What am I doing wrong? The thing is, if I take out the
Hardy> entire choose, and just use
Hardy> <xsl:sort select="code" />
Hardy> it seems to work.
Well, you seem to have all but worked it out - you can't have xsl:sort
anywhere except as an immediate child of xsl:for-each or xsl:apply-templates
in XSLT 1.0.
--
Colin Paul Adams
Preston Lancashire
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