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Re: <xsl:number> in XPath

2004-12-09 13:23:58
It's working now with

<xsl:apply-templates select="/menus/menu | 
(//menu)[$pos]/ancestor-or-self::menu/menu" />

Thanks, everybody...


Citando Marian Olteanu <mou_softwin(_at_)yahoo(_dot_)com>:

I want both the /menus/menu, the (//menu)[$pos] and their ancestors and
first
children, but i can't do something like

<xsl:apply-templates select="/menus/menu | (//menu)[$pos]" |
(//menu)[$pos]/menu
 | ancestor:menu[(//menu)[$pos]]/>

or is there something similar?
Sorry, I slipped an error first time.
<xsl:apply-templates select="/menus/menu | (//menu)[$pos] |
(//menu)[$pos]/menu
 | (//menu)[$pos]/ancestor::menu" />



=====
Marian
http://www.utdallas.edu/~mgo031000/



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