David
Ultimately i am trying to check if the items in $s1 can also be found in $s2.
For example -
$s1 would consist of 2 items, $s1/item/Milk and $s1/item/Sugar
$s2 would consist of 10 different items, Milk and Sugar are among them.
I've accomplished this using the for-each loop you suggested, however
i need a way to signal that ALL items have been found after the loop,
and not only some of them.
I'm thinking something like:
<xsl:for-each select="$s1/item[.=$s2/item]">
<!--now, try to place the items that it found matches for, into a
nodeset and compare it to the original $s1 itemset. If the results
from the for-each loop and the $s1 itemset contain the same items,
output COMPLETE MATCH-->
However, i'm not sure how to accomplish getting every matched item it
finds into a nodeset of some sort that i can use for a comparison
later on. Any help would be appreciated...I'm a beginner and
frustration is setting in, but so far you guys have helped me a good
deal. Thanks.
Chris
On Wed, 8 Dec 2004 22:41:37 GMT, David Carlisle
<davidc(_at_)nag(_dot_)co(_dot_)uk> wrote:
It's not clear why you are using recursion rather than just using
postion() or count to get this number, but perhaps that's just because
you have cut the example down, I didn't follow all the logic of your
stylesheet but can comment on some lines:
<xsl:with-param name="s1"
select="$s1/item[following-sibling]"/>
That selects all items that have a child called following-sibling so it
will be empty, I don't know which nodes you mean to select here but
perhaps
select="following-sibling::*"
<xsl:for-each select="$s1/item">
<xsl:variable name="sub1" select="."/>
<xsl:for-each select="$s2/item">
<xsl:if test="$sub1 = . ">
This is rather strange, it loops through all pairs of items in s1
and s1 but only does anything if the items are equal
so you could just select those pairs with a single xpath:
<xs:for-each select="$s2/item[.=$s1/item]">
which is more compact to write and at least gives the system a chance of
being a bit more efficient.
It seems that you want to use an integer counter as your main control
and repeatedly pass the whole of yor set $s1 and keep accessing $s1[$i]
this isn't the usual XSL way, normally you would just simply pass the
current node as a parameter, and then move control to teh following
sibling, without ever needing your integer position variable.
David
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