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RE: HOW XSLT WILL BE, WHEN XML2XML TRANSFORMATION

2004-12-04 09:11:26
This is very straightforward.

<xsl:template match="para">
  <xsl:apply-templates/>
</xsl:template>

<xsl:template match="equation">
<eqn><xsl:apply-templates/></eqn>
</xsl:template>

<xsl:template match="para/text()">
<p><xsl:apply-templates/></p>
</xsl:template>

Michael Kay
http://www.saxonica.com/


I am processing XML to XML transformation by using xslt, in 
the meantime 
I would like to clarify with you regarding the below one:

Input XML:
<para>
Text before equation
    <equation>Equation text</equation>
        Text before/after equation
    <equation>Equation text</equation>
Text after equation
</para>


Output XML:
<p>Text before equation</p>
<eqn>Equation text</eqn>
<p>Text before/after equation</p>
<eqn>Equation text</eqn>
<p>Text after equation</p>

Please advise, how can I able to get above Output XML by 
using xslt, and 
how the XSLT will be?

Best regards
Arul Kumar


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