Hi Dave,
Please try this XSL. It uses the Muenchian
technique.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:key name="by-group-name" match="group"
use="@name" />
<xsl:template match="/root">
<root>
<xsl:for-each select="group[generate-id(.) =
generate-id(key('by-group-name', @name)[1])]">
<group name="{(_at_)name}">
<xsl:for-each select="key('by-group-name',
@name)">
<xsl:copy-of select="*"/>
</xsl:for-each>
</group>
</xsl:for-each>
</root>
</xsl:template>
</xsl:stylesheet>
Regards,
Mukul
--- Dave Roe <david_roe(_at_)mac(_dot_)com> wrote:
I have this XML representing 2 groups (spread across
4 group elements):
<root>
<group name="group1">
<entry name="entry1" />
<entry name="entry2" />
</group>
<group name="group1">
<entry name="entry3" />
</group>
<group name="group2">
<entry name="entry4" />
<entry name="entry5" />
</group>
<group name="group2">
<entry name="entry6" />
</group>
</root>
What would be the best approach to turn it into the
following output,
where the name of the group is used as the
identifier of what should be
a unique group element?
<root>
<group name="group1">
<entry name="entry1" />
<entry name="entry2" />
<entry name="entry3" />
</group>
<group name="group2">
<entry name="entry4" />
<entry name="entry5" />
<entry name="entry6" />
</group>
</root>
Right now, I just need someone to point me in the
right direction to
get me started.
Thanks,
/dave
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