xsl-list
[Top] [All Lists]

graph-traversal query

2005-01-28 07:26:54
Hi

This is a question I asked earlier on the forum and was advised by Wendell to send it as a seperate query so I could get feedback from a wider audience.

I'm educating myself on XSLT and XPath but until the two books Ive recently ordered arrive, I'd need some help from the experts to help me proceed.

My query is thus:

Im finding the dynamic assigning and traversing process in XSL quite confusing. Is there a logical way of traversing through a tree to determine the grandchild of an element albeit indirectly. So I know that my XML file is as below

-----------------------
<DEFCONCEPT id="10180" name="Car">
       <PARENT>
           <CONCEPT name="Automobile" ref="10181"/>
       </PARENT>
       <CHILD>
           <CONCEPT name="Toyota" ref="10235"/>
       </CHILD>
</DEFCONCEPT >
<DEFCONCEPT id="10235" name="Toyota">
       <PARENT>
           <CONCEPT name="Car" ref="10180"/>
       </PARENT>
       <CHILD>
           <CONCEPT name="Corolla" ref="10279"/>
       </CHILD>
</DEFCONCEPT >
<DEFCONCEPT id="10279" name="Corolla">
       <PARENT>
           <CONCEPT name="Toyota" ref="10235"/>
       </PARENT>
</DEFCONCEPT >
-----------------------
and I want to reach the <DEFCONCEPT name="Corolla"> from the node <DEFCONCEPT name="Car"> because I have a query to determine the existence of a kind_of Car 'Corolla' irrespective of the case (upper or lower) in which it has been written and where in the hierarchy it exists. How will it be possible using XSLT?


Thanks
Rahil



--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--



<Prev in Thread] Current Thread [Next in Thread>