I want this to be generic.
The tag/attribute names are not known. The 'e' was just part of the example.
Thanks
-----Original Message-----
From: Joris Gillis [mailto:roac(_at_)pandora(_dot_)be]
Sent: Tuesday, January 25, 2005 9:04 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] generic sort based on attribute names
Tempore 01:45:12, die 01/25/2005 AD, hinc in
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com scripsit Chaitanya Desai
<cdesai(_at_)syncata(_dot_)com>:
Can u please explain how the node-set function could help in this
context?
Sure...
In stead of the the clumsy 'substring()' approach, you could use a result
tree fragment, given that you have got an extension function that can
convert it to a node-set.
e.g.
<xsl:sort
select="xx:node-set($sortkey)//e[position()=count(current()/preceding-sibling::e)]"/>
with this template:
<xsl:template match="e" mode="sortkey">
<e>
<xsl:apply-templates select="@*" mode="sortkey">
<xsl:sort select="." data-type="string"/>
</xsl:apply-templates>
</e>
</xsl:template>
(not tested)
regards,
--
Joris Gillis (http://www.ticalc.org/cgi-bin/acct-view.cgi?userid=38041)
"Φιλήκοον ειναι μαλλον η φιλόλαλον" -
Κλεόβουλος
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