Hi,
Pls Ignore this posting.
Regards,
Omprakash.V
omprakash(_dot_)v(_at_)pol
aris.co.in To:
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
cc: (bcc: omprakash.v/Polaris)
01/25/2005 Subject: [xsl] recursive
template
04:29 PM
Please respond
to xsl-list
Hi,
Iam having difficulty in getting this recursive call to a template
to work as expected.
I call once from main as follows:
<xsl:call-template name="study">
<xsl:with-param name="attrname" select="@name"/>
<xsl:with-param name="path" select="@type"/>
</xsl:call-template>
And I have the following in my 'study' template:
<xsl:template name="study">
<xsl:param name="attrname"/>
<xsl:param name="path"/>
<xsl:for-each select="child::*">
<!-- (A) -->
<xsl:message>name = <xsl:value-of select="@name"/></xsl:message>
<xsl:message>type = <xsl:value-of select="@type"/></xsl:message>
<!-- just a check to recurse selectively into some child nodes -->
<xsl:if test="not(substring-before(@type,':')='ps')">
<!-- (B) -->
<xsl:call-template name="study">
<xsl:param name="attrname" select="@name"/>
<xsl:param name="path" select="@type" />
</xsl:call-template>
</xsl:if>
</xsl:for-each>
</xsl:template>
At (A), I would like to print out recursively the name and type attributes
of all the child nodes.
But the value remains constant, the same as I passed in from main.
I can however see that the correct value gets printed at (B).
Any suggestions are welcome.
Regards,
Omprakash.V
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