Hi,
I appreciate your reply. Prabably I should have been more clear in my
mail. When I mentioned top-level (school in my case) I didn't exactly mean
top-level but inside of the top-level element but outside of the actual
root (student) where my student data is.
I did note the point on the 'resulttreefragment part'.
Thanks.
Omprakash.V
David Carlisle
<davidc(_at_)nag(_dot_)co(_dot_)u To:
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
k> cc:
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com, (bcc: omprakash.v/Polaris)
Subject: Re: [xsl] finding nodes
01/24/2005 07:31
PM
Please respond
to xsl-list
<xsl:variable name="nset">
<xsl:copy-of select="/campus[(_at_)name = $value]"/>
</xsl:variable>
as has been said already in thi sthread, don't (ever) do that, which
generates a result tree fragment (and is expensive even in XSLt2 where
it would generate a node set)
do
<xsl:variable name="nset" select="/campus[(_at_)name = $value]"/>
However there will only be one element node below / so thi snode set
will have at most one element in it, depending on whether the top level
element is a campus element with that attribute. Is that really what you
want?
and then define the template match = "campus". But
wouldn't
<xsl:template match="campus"> match other campus nodes as well.
It would match, but unless you apply templates to those other nodes,
they would never be processed.
David
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