You can use count(onderwerpen), but in this case it's better just to use
last(), as has been suggested.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: gerritjan [mailto:gerritjankoekkoek(_at_)mac(_dot_)com]
Sent: 23 January 2005 10:41
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Determine last element before applu-templates
Hello,
Is there a 'best practise' for determine how many elements are in a
document.
My schema looks like this:
<xsd:element name = "onderwerpen">
<xsd:complexType>
<xsd:sequence>
<xsd:element ref = "onderwerp"/>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
1 to many 'onderwerp' within 'onderwerpen'
My xslt looks like this:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:template match="onderwerpen">
<xsl:apply-templates select="onderwerp">
<xsl:with-param name="last_element">3</xsl:with-param>
</xsl:apply-templates>
</xsl:template>
<xsl:template match="onderwerp">
<xsl:param name="last_element"/>
<xsl:if test="position()=$last_element">
<xsl:text>Something specific for last element</xsl:text>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
The hard-code '3' should be determined before; based on the number of
elements 'onderwerp'
Any suggestions how this is best handled?
Gerritjan Koekkoek
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail:
<mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--