Hi,
In XSLT 2, if you create a nodeset as a variable, is there any way to
make it inherit the stylesheet's default namespace?
My stylesheet creates a lot of these variables, which it either copies
straight to output, or processes. This is fine unless the stylesheet has
a default namespace - which is needed for the xhtml output to have a
namespace declaration.
ie:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="2.0"
xmlns="http://www.w3.org/1999/xhtml"; <----- default breaks it
>
If the default is set, the variables copies to output are decorated with
empty namespace declarations (xmlns=""), and the templates that process
the variables no longer do so.
Putting a declaration in the variables worked, but I got errors in cases
that mixed the input and another variable and a hardcoded default, eg:
<xsl:variable name="head">
<xsl:copy-of select="$head/*"/>
<xsl:copy-of select="head/*"/>
<script src="product.js" xmlns="http://www.w3.org/1999/xhtml"/>
<style href="product.css" xmlns="http://www.w3.org/1999/xhtml"/>
</xsl:variable>
The only way that worked was to prefix all the tags in the variables:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:f="http://www.w3.org/1999/xhtml";
xmlns="http://www.w3.org/1999/xhtml";
version="2.0"
exclude-result-prefixes="f"
>
[...]
<xsl:variable name="head">
<xsl:copy-of select="$head/*"/>
<xsl:copy-of select="f:head/*"/>
<f:script src="product.js" xmlns="http://www.w3.org/1999/xhtml"/>
<f:style href="product.css" xmlns="http://www.w3.org/1999/xhtml"/>
</xsl:variable>
Which I don't like doing because I'm lazy and because it seems
unnecessary. Am I missing something?
Cheers,
Tom SW
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