I believe this would require that you sort on @uid. And I also believe
preceeding-sibling selects all preceeding siblings.
I would try something like this ...
<xsl:template match="/">
<xsl:apply-templates select="//user" mode="check-dups">
<xsl:sort select="@uid"/>
</xsl:apply-templates>
</xsl:template>
<xsl:template match="user" mode="check-dups">
<xsl:if test="preceding-sibling::user/@uid=(_at_)uid">
<xsl:message>oops</xsl:message>
</xsl:if>
...
Douglas Ross
Developer, HTML UI Framework
Kronos
E-mail: dross(_at_)kronos(_dot_)com
www.kronos.com
-----Original Message-----
From: dan sherman [mailto:h8_bsod(_at_)yahoo(_dot_)com]
Sent: Thursday, January 20, 2005 11:36 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] using boolean to compare id numbers
Will that test that no two users not just the
preceding user have the same uid numbers?
--- David Carlisle <davidc(_at_)nag(_dot_)co(_dot_)uk> wrote:
lots of ways, depending what you want to do. The
most general way is to
use any of the grouping methods (see faq or jeni's
site) and see if any
group has two items in it. If you are just
processing all the users and
want to generate an error message if you've seen
this uid before I'd do
<xsl:template match="user">
<xsl:if test="preceding-sibling::user/@uid=(_at_)uid">
<xsl:message>oops</xsl:message>
</xsl:if>
....
David
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