Hi Roy,
Have you tried to insert spaces in 6>$n --> 6 > $n? I count another 4
times. You do it correctly with 'and' and 'or'.
HTH,
<prs/>
-----Original Message-----
From: r(_dot_)moe(_at_)student(_dot_)qut(_dot_)edu(_dot_)au
[mailto:r(_dot_)moe(_at_)student(_dot_)qut(_dot_)edu(_dot_)au]
Sent: Miércoles, 19 de Enero de 2005 12:13 p.m.
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] How can I conditionaly assign a node-set to my variable?
How can I conditionaly assign a node-set to my variable?
Variable needs to have local scope.
Obviously I can't use <xsl:value-of.../>.
I get the error message:
"Reference to variable or parameter 'firstTableRows' must evaluate to a node
list."
Code:
<xsl:variable name="firstTableRows">
<xsl:choose>
<xsl:when test="6>$n and $hasP">
<xsl:value-of select="channel[6>id or id='P']"/>
</xsl:when>
<xsl:when test="6>$n">
<xsl:value-of select="channel[6>id]"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="channel[6>id]"/>
</xsl:otherwise>
</xsl:choose>
</xsl:variable>
Thanks,
Roy
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