What I am interested in, is the level of Y nodes.
If I wanted the top two levels, I could easily do this in xpath using
count(ancestor::Y).
The problem is that I cannot readily count all descendants -
count(descendant::Y) will not count the number of levels but
the total
number of Y nodes that are beneath the current Y node.
Is there a way for such counting in XPath?
I want all except the buttom 1, 2, 3 or more levels. The exact amount
determined from a parameter.
I could have something like [not(X)] for leaf nodes,
[not(X/Y/X)] for the
the buttom 2 levels (leaf nodes
and one level up, counting from the leaf). But as the number
of levels are
to be determined dynamically,
If I've understood you correctly, you want to count the number of <Y>
elements at a given level?
If so the brute force method of using two-passes in a single stylesheet
will work:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:param name="level" select="3"/>
<xsl:variable name="structureWithLevels">
<xsl:apply-templates mode="addLevels"/>
</xsl:variable>
<xsl:template match="@*|node()" mode="addLevels">
<xsl:copy>
<xsl:apply-templates select="@*|node()"
mode="addLevels"/>
</xsl:copy>
</xsl:template>
<xsl:template match="Y" mode="addLevels">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:attribute name="level">
<xsl:value-of select="count(ancestor::Y|.)"/>
</xsl:attribute>
<xsl:apply-templates mode="addLevels"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/">
<div>
<xsl:copy-of select="$structureWithLevels"/>
<xsl:value-of
select="count($structureWithLevels//Y[(_at_)level = $level])"/>
</div>
</xsl:template>
</xsl:stylesheet>
Here the level of each <Y> element is added to it using the moded
identity transform - with that information you can then work out what
ever you want.
Cheers
andrew
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