select="key('professionlevelkey','$referid')">
it was a typo, I used $referid instead '$referid'.
-Ranjan
--- David Carlisle <davidc(_at_)nag(_dot_)co(_dot_)uk> wrote:
select="key('professionlevelkey','$referid')">
You have used the string '$referid' as the key
value. You probably have
no key with that value. If you want the value of the
variable referid
then you want $referid not '$referid'. Although if
that is the only
place you use that variable, which seems likely then
you don't need a
variable at all, you could just use @levelref
David
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