How about
//tree_node[(_at_)id=9]/ancestor::tree_node |
//tree_node[(_at_)id=9]following-sibling::tree_node |
//tree_node[(_at_)id=9]preceding-sibling::tree_node
On Sat, 19 Feb 2005 01:16:58 +1000, Adam J Knight
<adam(_at_)brightidea(_dot_)com(_dot_)au> wrote:
Hi guys,
Another chapter in this tragedy.
Question:
The expression '//tree_node[(_at_)id=9]/ancestor::tree_node' returns a nodeset
containing node with id(7). I have verified this with xpath visualizer.
How do I return the ALL siblings of this node also.
The result being
Node(id=7)
Node(id=8) : sibling of Node(id=7)
Node(id=9) : sibling of Node(id=7)
Node(id=14) : sibling of Node(id=7)
HELP APPRECIATED!!!!
ALL TO0 FAMILIAR XML STRUCTURE:
<tree>
<tree_node id="7" value="Test Level One A">
<tree_node id="8" value="Test Level Two A"/>
<tree_node id="9" value="Test Level Two B">
<tree_node id="11" value="Test Level Three B"/>
<tree_node id="10" value="Test Level Three A">
<tree_node id="12" value="Test Level Four A"/>
<tree_node id="13" value="Test Level Four B"/>
</tree_node>
</tree_node>
<tree_node id="14" value="Test Level Two C"/>
</tree_node>
</tree>
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