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Adding element to xml snippet using xslt

2005-02-17 08:55:31
Hi:
I have the following xml snippet --
<abc:configuration xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"; xsi:schemaLocation="http://oracle.com/xmlns/abcst/configuration configuration.xsd" locale="en" webcache="false" rmi="true">
<started status="true"></started>
<server></server>
..
....
</abc:configuration>

I need to convert this to the following result xml:
<abc:configuration
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";
xsi:schemaLocation="http://oracle.com/xmlns/abcst/configuration configuration.xsd" webcache="false" useMgmt="true" metadata="true">

<drillOutDir></drillOutDir>
<started status="true"></started>
<server></server>
.....
</abc:configuration>

I have the following xsl, that converts the initial snippet to the resultant but i observed that the <started> element occurs before the <drillOutDir> element. How can I change my xsl to achieve the above result xml in the exact order?

<xsl:template match="abc:configuration">
<xsl:copy>
<xsl:copy-of select="@*[local-name() != 'rmi' and local-name() != 'locale']"/>
<xsl:attribute name="useMgmt">
<xsl:text>true</xsl:text></xsl:attribute>
<xsl:attribute name="metadata"><xsl:text>true</xsl:text></xsl:attribute>
<xsl:apply-templates/>
</xsl:copy>
<xsl:text></xsl:text>
</xsl:template>
<xsl:template match="server"> <xsl:element name="drillOutDir"> </xsl:element>
</xsl:template>

Please help.
Thanks.


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