RE: Replace function and apostrophes

&apos; is translated to ' by the XML parser before the XPath processor sees
it. So the XPath string literal is ''' which is clearly wrong. In fact,
there's no point using &apos here: you only need it when the attribute
delimiters are apostrophes.

XPath 2.0 allows the delimiter of a string literal to be doubled withing the
string, so you can write

"replace(., '''', '\\''')" 

Alternatively, use

select='replace(., "&apos;", "\\&apos;")'

or define the strings as variables:

<xsl:variable name="x" as="xs:string">'</xsl:variable>
<xsl:variable name="x" as="xs:string">\\'</xsl:variable>

select="replace(.,$x,$y)"

Michael Kay
http://www.saxonica.com/

-----Original Message-----
From: Andrew Welch [mailto:ajwelch(_at_)piper-group(_dot_)com] 
Sent: 17 February 2005 14:35
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Replace function and apostrophes


I'm trying to replace all occurances of apostrophes with \' 
as part of a
variable's select statement:

<xsl:variable name="foo" select="replace(., '&apos;', '\\&apos;'"/>

This fails with "invalid character in expression '\'" - any 
ideas on how
to do this?

Thanks
andrew 

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