Hello Joris,
Thank you for your prompt reply. The solution works well.
Being new to XSLT I'm a little unsure of exactly what the pattern in the
'use' attribute value in the xsl:key element is doing.
Could you please explain it in a little more detail.
Thanks
Paul
-----Original Message-----
From: Joris Gillis [mailto:roac(_at_)pandora(_dot_)be]
Sent: 15 February 2005 18:48
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] FW: Dealing with mixed content
Tempore 19:31:36, die 02/15/2005 AD, hinc in
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
scripsit Paul Clarke
<pclarke(_at_)rcpsolutions(_dot_)com>:
Hello,
Apologies inadvance for the 'XSL 101' nature of this question but I'm
new to XSL.
I receive XML from an automate conversion process, over which I have
no control.
Example:
<block >Text <font font-weight="bold">more text</font> more
text<sr/>more text. <hr/>more text <sr/>more text.</block>
The <sr/> elements can be ignored but the <hr/> element indicates that
an exisitng <P> element should be terminated and a new <P> element
started.
From the above sample the output would be:
<P>Text <f>more text</f> more text more text. </P>
<P>more text more text</P>
Hi,
This is a grouping problem. Numerous techniques are available for solving
problems like this.
Here you have one:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:key name="group" match="node()" use="generate-id((.. |
preceding-sibling::hr)[last()])"/>
<xsl:template match="block">
<xsl:copy>
<xsl:for-each select="hr|.">
<p>
<xsl:apply-templates
select="key('group',generate-id())"/>
</p>
</xsl:for-each>
</xsl:copy>
</xsl:template>
<xsl:template match="sr | hr"/>
<xsl:template match="font">
<f>
<xsl:apply-templates/>
</f>
</xsl:template>
</xsl:stylesheet>
regards,
--
Joris Gillis (http://www.ticalc.org/cgi-bin/acct-view.cgi?userid=38041)
Spread the wiki (http://www.wikipedia.org)
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