Hi,
If you know the structure of the input xml will not change then you may use
the following template.
<xsl:template match="ITEM">
<xsl:if test="*[1]/VALUE/text() = 'AA' and *[2]/SCORE/text()='1'">
<xsl:value-of select="."/>
</xsl:if>
</xsl:template>
Cheers,
Omprakash.V
"Steve W"
<lsl(_at_)btconnec To:
<xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
t.com> cc: (bcc: omprakash.v/Polaris)
Subject: [xsl] Selecting a node
based on two sub-element values
02/15/2005
01:41 PM
Please
respond to
xsl-list
Hi,
I have XML that looks like this :
<DATA>
<ITEM>
<SUBDATA1>
<VALUE>AA</VALUE>
</SUBDATA1>
<SUBDATA2>
<SCORE>1</SCORE>
</SUBDATA2>
</ITEM>
<ITEM>
<SUBDATA1>
<VALUE>BB</VALUE>
</SUBDATA1>
<SUBDATA2>
<SCORE>1</SCORE>
</SUBDATA2>
</ITEM>
<ITEM>
<SUBDATA1>
<VALUE>AA</VALUE>
</SUBDATA1>
<SUBDATA2>
<SCORE>3</SCORE>
</SUBDATA2>
</ITEM>
</DATA>
How do I select all the <ITEM> elements where <VALUE> elements contain 'AA'
and <SCORE> elements contain '1' ?
Thanks
Steve
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