So you wish to count unique models.. This is a
grouping problem... (and Muenchian grouping technique
first comes to my mind)
Please try this XSL -
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="text" />
<xsl:key name="by-model" match="car" use="model" />
<xsl:template match="/cars">
<xsl:variable name="modelcount">
<xsl:for-each select="car[generate-id(.) =
generate-id(key('by-model',model)[1])]">
1
</xsl:for-each>
</xsl:variable>
Total no of models - <xsl:value-of
select="string-length($modelcount) -
string-length(translate($modelcount,'1',''))" />
</xsl:template>
</xsl:stylesheet>
Regards,
Mukul
--- Marcos Hercules dos Santos <mhercules(_at_)gmail(_dot_)com>
wrote:
Thanks Mukul Gandhi,
the stage 1 from summing used by exemplification
- cars. It's all ok, cool.
thanks
Going on, based in the same question, how must do
I to proceed to
group a tag and totalize itself.
Using the same example:
<cars>
<car>
<model>V667320</model>
<name>Sportage</name>
<categ>sport</categ>
</car>
<car>
<model>M382932</model>
<name>Silverado</name>
<categ>pick-up</categ>
</car>
Imagine that the first element (model) be written
five times, the
second model two times, and other any model four
times. Supposing
that this could be a greatest structure with 25
models and many
occurences to it , how to do to generate the total
number of models
and not occurences
The Total number to display = 25
if consider the three , then = 3 and not
5+2+4
Marcos Hercules dos Santos
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