Read a good book and also these examples from Dave Pawson's XSL-FAQ:
http://www.dpawson.co.uk/xsl/sect2/identity.html
http://www.dpawson.co.uk/xsl/sect2/N1930.html
Cheers,
Dimitre Novatchev
On Fri, 11 Feb 2005 15:56:58 -0700, Karl Stubsjoen
<kstubs(_at_)gmail(_dot_)com> wrote:
Seems like this is pretty standard:
SAMPLE_001:
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
But then I've also seen this:
SAMPLE_002:
<xsl:template match="/ | @* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
How do they compare? I make not of the SAMPLE_001 within the xsl:copy
there are 2 apply templates, what does each do?
Then, understanding what is happening, is the following sample true
that this will strip an XML doc of all attribute elements?
SAMPLE_003:
<xsl:template match="*">
<xsl:copy>
<xsl:apply-templates select="*"/>
</xsl:copy>
</xsl:template>
And finally, when I identity transform the following my document i
quadrupled in size, but I though I was following standard practices
from previous example.
SAMPLE_004:
<xsl:template match="*">
<xsl:copy>
<xsl:apply-templates select="*"/>
<xsl:apply-templates />
</xsl:copy>
</xsl:template>
Ahh, I think I understand what is going on in SAMPLE_004 (please
confirm) I am basically applying templates for all nodes twice and in
the case of lets say SAMPLE_001 the first apply-templates simply gets
all attributes, the 2nd then gets all nodes. We'd call this a
recursive call on the node set?
Karl
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