Couldn't you have something like:
<xsl:template match="item[contains(text(),'%')]">
On Fri, 11 Feb 2005 12:20:41 +0100, news(_at_)swisslab(_dot_)de said:
Hello List,
I have the following XML in form of a variable:
input:
<XML>
<item>vlue</item>
<item>%special value%</item>
<item>vlue</item>
<item>%special value%</item>
<unkown_items/>
<unkown_items/>
</XML>
I want to transform the variable into another variable, having all
<item>s
values which contain a '%' changed into other values. (like "super
special
value" instead of "%special value%")
My problem is, that there are planty of unknown items in the variable
that I
dont know and that might change. But I want the XML structure to stay as
it
is, and just replace some items values.
output:
<XML>
<item>vlue</item>
<item>super special value</item>
<item>vlue</item>
<item>super special value</item>
<unkown_items/>
<unkown_items/>
</XML>
How can I do this?
thanks!
Jan
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