Thanx joris for you answer. The problem was actually your 1st solution: I had
2 XML element with the same 'id' attributes...
-----Message d'origine-----
De : Joris Gillis [mailto:roac(_at_)pandora(_dot_)be]
Envoyé : mercredi 9 février 2005 10:59
À : xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Objet : Re: [xsl] Select and display a node
Tempore 09:57:50, die 02/09/2005 AD, hinc in
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com scripsit Sébastien Bicaïs
<s(_dot_)bicais(_at_)Megalos(_dot_)net>:
<xsl:template match="rss/channel" >
<xsl:for-each select="item/page[(_at_)id=456]">
id = <xsl:value-of select="@id"/>
</xsl:for-each>
</xsl/template>
But when I run this, I get "id = 456" twice..
Any suggestion welcome
Hi,
I can only see 2 possible explanations:
1) Your real input XML contains elements with the same 'id' attributes.
2) You're not using any tool that displays error messages.
You tried this first:
<xsl:template match="rss/channel" >
<xsl:for-each select="item/page">
id = <xsl:value-of select="@id"/>
</xsl:for-each>
</xsl:template>
Which resulted (correclty) in 2 times "id = ..."
And then you changed to:
<xsl:template match="rss/channel" >
<xsl:for-each select="item/page[(_at_)id=456]"> id = <xsl:value-of
select="@id"/> </xsl:for-each> </xsl/template>
Which is not well-formed xml ('</xsl/template>') and caused the ouput file not
to be updated. Thus creating the false impression that it returned 2 times "id
= ..." again.
regards,
--
Joris Gillis (http://www.ticalc.org/cgi-bin/acct-view.cgi?userid=38041)
Fiat W3C in tenebris
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