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RE: Selecting last text() from fragment of unknown depth?

2005-02-05 09:53:01
With this template

<xsl:template 
match="submission.excerpt//node()/@*|submission.excerpt//node()">
<xsl:copy><xsl:apply-templates select="./@*|./node()" /></xsl:copy>
</xsl:template>

have I made it impossible to also transform (inline) the last 
occurring 
textnode beneath submission.excerpt/node()?

Nothing is impossible, but selecting whether you're the last text node in a
subtree is a little tricky in 1.0.  I often find it useful to work back from
a 2.0 solution, which you could do by adding the template rule:

<xsl:template match="text()[. is
(ancestor::submission.excerpt//text())[last()]]" priority="5"
  <xsl:value-of select="."/>...
</xsl:template>

You haven't got the "is" operator in 1.0, but you can replace (A is B) by
(generate-id(A) = generate-id(B)).

This solution could be rather expensive if the number of text nodes in a
submission.excerpt is large.

Michael Kay
http://www.saxonica.com/


So far all my recursion attempts (looking for 
node()[last()][self::text()] 
at each level) have yielded 3 variations: *only* the last 
text(), everything 
*except* the last text(), or the whole thing and then the last text() 
appended again.

<xsl:choose>
<xsl:when test="./node()[last()][self::text()]">
      <xsl:copy>
              <xsl:apply-templates 
select="./@*|./node()[position() != last()]" />
              <xsl:value-of select="./node()[last()]" />...
      </xsl:copy>
</xsl:when>
<xsl:otherwise>
      <!-- look again next level, etc -->
</xsl:otherwise>
</xsl:choose>

It's meant to take an XHTML string (truncated from db then 
made well-formed 
again by PHP5's loadHTML method) and replace the end of the 
last text() -- 
after the last occuring space character -- with an ellipsis, 
which I've now 
heard 3x is 'impossible' in XSLT 1.0 but it's not official 
till I've heard 
it here.

Undying gratitude,
-Adam.

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