Hi,
I have a xsl stylesheet that uses str:split to convert a value into
fragment.
e.g.
...
<id>10.20.50</10>
...
Becomes
<root xmlns="http://www.w3.org/1999/XSL/Transform";>
<pg id=10.20.50>
<s>10</s>
<s>20</s>
<s>50</s>
</pg>
</root>
Everything works great except, my root node is output with the default
namespace. This causes me much grief when I try to access a
node by name
with an XPath expression.
My question is. How do I reference a node in the namespace context as
noted above,
Just declare xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; in your
stylesheet and then use e.g. xsl:root/xsl:pg/xsl:s
or how can I prevent str:split from outputting
the default
namespace?
Don't set the default namespace to be the XSLT one in the str:split template.
Cheers,
Jarno
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--