The elements that declare variables are called variable binding elements.
These are xsl:variable and xsl:param. The xsl:with-param element is not a
variable binding element; it does not declare a variable. Rather it assigns
a value to the variable declared in the xsl:param element of the called
template. Therefore, you can't reference $p1 in the second with-param.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Wim Janssen
[mailto:Wim(_dot_)Janssen(_at_)student(_dot_)luc(_dot_)ac(_dot_)be]
Sent: 03 February 2005 18:46
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] with-param problem
Hi,
I'm working on a master thesis about XSLT.
I found a problem and I don't know wether it is a bug in
saxon (version 8.0).
Take a look a this little program
<xsl:template match="/a">
<xsl:element name="S">
<xsl:call-template name="f">
<xsl:with-param name="p1" select="3"/>
<xsl:with-param name="p2" select="$p1 + 2"/>
</xsl:call-template>
</xsl:element>
</xsl:template>
<xsl:template name="f">
<xsl:param name="p1"/>
<xsl:param name="p2"/>
</xsl:template>
The problem is the param named "p2". It uses param "p1".
Why is that not
allowed in XSLT? Or is it maybe a bug in Saxon?
I'm sorry for my terrible English!
greetings
Wim Janssen
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