This would work if you defined "/" in your xsl:decimal-format as a
grouping-separator. (It might, anyway: format-number() in XSLT 1.0 is badly
under-specified).
A more orthodox approach would be a combination of substring() and concat().
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Varley, Roger [mailto:Roger(_dot_)Varley(_at_)atosorigin(_dot_)com]
Sent: 03 February 2005 11:55
To: Xsl-List (E-mail)
Subject: [xsl] Format-number problem
Hi
My XML data contains an element whose contents represent a
date in YYYYMMDD format. I'm trying to get this to produce
YYYY/MM/DD in the output. I've tried
<xsl:value-of
select="format-number(//E1EDK03[IDDAT='012']/DATUM,'####/##/##')"/>
where DATUM contains 20050115 but I get "20050115//" in the
output. I'm obviously misunderstanding how to use
format-number. Am I trying the right approach here?
Regards
Roger
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