In the XPath data model, namespaces are not attributes. So @* doesn't select
them. To copy namespaces you need to use xsl:copy-of select="namespace::*"
However if instead of
<xsl:variable name="rootnode" select="name(.)"/>
<xsl:element name="{$rootnode}">
you do
<xsl:copy>
then namespaces will be copied automatically. (In fact, one of the reasons
for using xsl:element in preference to xsl:copy is when you don't want
namespaces copied.)
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: omprakash(_dot_)v(_at_)polaris(_dot_)co(_dot_)in
[mailto:omprakash(_dot_)v(_at_)polaris(_dot_)co(_dot_)in]
Sent: 31 March 2005 14:06
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] copying xmlns: attribute
Hi,
Got this far by myself.
Iam using the following code to copy an element
along with its
attibutes to the result tree from a context node which is
elsewhere in the
document. The context node is in fact the root element.
However, the xmlns:
attribute is not getting copied.
<xsl:template match="/">
<xsl:for-each select="//root/*[1]">
<xsl:variable name="rootnode" select="name(.)"/>
<xsl:element name="{$rootnode}">
<xsl:copy-of select="@*"/>
<xsl:apply-templates select="/" mode="inside">
<xsl:with-param name="rootnode" select="$rootnode"/>
</xsl:apply-templates>
</xsl:element>
</xsl:for-each>
</xsl:template>
I have used xsl:copy-of select="@*" earlier and I know that it copies
xmlns: attributes.
Also, in the inner call to apply-templates, I have to select
"/" once again
with a different mode as otherise only one node is getting
copied if I use
@*|node()
My xhtml snippet is as follows:
<table>
<tr>
<root>
<slideshow xmlns="urn:hl7-org/v3" title="Sample Slide Show"
date="Date of
publication" author="Yours Truly">
<td><a href="file:///">
:
:
:
</slideshow>
Hoping to get a quick reply.
Cheers,
Omprakash.V
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