Why the pc element?
You have an unique ID by concat tc id and pc/status id
tc1: status id = 1231
1232
1231
tc2: status id = 1245
1241
tc3: status id = 1251
So i should yield:
tc1: 1231
1232
tc2: 1245
1241
tc3: 1251
????
Sven
Michael Kay wrote:
And my answer is unchanged.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Sven Waibel [mailto:sven(_dot_)waibel(_at_)imbus(_dot_)de]
Sent: 23 March 2005 10:22
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Unique IDs?
That's the correct xml:
<tc id="123">
<pc>
<status id="1" name="Status 1"/>
<status id="2" name="Status 2"/>
<status id="1" name="Status 1"/>
</pc>
</tc>
<tc id="124">
<pc>
<status id="5" name="Status 5"/>
<status id="1" name="Status 1"/>
</pc>
</tc>
<tc id="125">
<pc>
<status id="1" name="Status 1"/>
</pc>
</tc>
Michael Kay wrote:
Your stylesheet is giving you exactly what you asked for:
it's outputting
the Status value only if it is the first one with that
combination of id's.
To treat the contents of each <pc> as a separate group you
will need to
factor the identity (generate-id()) of the pc element into
the key value.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Sven Waibel [mailto:sven(_dot_)waibel(_at_)imbus(_dot_)de]
Sent: 23 March 2005 08:38
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Unique IDs?
Good morning!
in my xsl:
<xsl:key name="ids" match="tc/pc/*[(_at_)id]"
use="concat(../../@id,@id)" />
<xsl:template match="pc">
<xsl:apply-templates select="*[(_at_)id and generate-id(.)=
generate-id(key('ids', concat(../../@id,@id)))]" />
</xsl:template>
<xsl:template match="tc/pc/*[(_at_)id]">
<fo:block><xsl:value-of select="@name" /></fo:block>
</xsl:template>
my xml:
<tc id="123">
<pc>
<status id="1" name="Status 1"/>
<status id="2" name="Status 2"/>
<status id="1" name="Status 1"/>
</pc>
<pc>
<status id="5" name="Status 5"/>
<status id="1" name="Status 1"/>
</pc>
<pc>
<status id="1" name="Status 1"/>
</pc>
</tc>
The current output looks as followed:
"pc1" Status 1
Status 2
"pc2" Status 5
"pc3"
The output should look as followed:
"pc1" Status 1
Status 2
"pc2" Status 5
Status 1
"pc3" Status 1
Status No. must not exist more than one in one "pc".
What's wrong with my Stylesheet?
Thanks
Best regards
Sven
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