thanks a lot for this good help,
it works!
with best greating
henry
--- JBryant(_at_)s-s-t(_dot_)com wrote:
If you need to something only when the Duration
element is present:
<xsl:template match=" Group">
<xsl:if test="Duration">
<!-- Do something -->
</xsl:if>
</xsl:template>
If you need to do something when the Duration
element is present and
something else when it is not:
<xsl:template match=" Group">
<xsl:choose>
<xsl:when test="Duration">
<!-- Do something -->
</xsl:when>
<xsl:otherwise>
<!-- Do something else -->
</xsl:otherwise>
</xsl:choose>
</xsl:template>
If that doesn't work, post small (but complete
enough to show the problem)
XML and XSL files, so we can see more detail.
Remember to paste the XML
and XSL into the body of your message, since the
list (thankfully) doesn't
take attachments.
Jay Bryant
Bryant Communication Services
(presently consulting at Synergistic Solution
Technologies)
henry human <henry_human(_at_)yahoo(_dot_)de>
03/17/2005 04:52 PM
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Subject
[xsl] how check if the node exit and display content
of it
i create xml files .
the node "Group" could has
child:
<Group>
<undergroups>
<Duration>1:9</Duration>
<description>Waiting for data</description>
</undergroups>
</Group>
or could be without child:
<Group>
</Group>
How could i check in my xsl file if this node
has some child (f.example <Duration>
or <description>)
after that i will to display the
Result(f.example Waiting for data) in browser
i tied it with xsl:if test and xsl:variable
but could'nt use it correctly!
thanks
henry
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