You could do that with a named template:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:transform version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html"/>
<xsl:template match="page">
<html>
<head>
</head>
<body>
<div id="header">
<xsl:call-template name="header"/>
</div>
<div id="main">
<xsl:call-template name="main"/>
</div>
</body>
</html>
</xsl:template>
<xsl:template name="header">
<!-- do stuff here -->
</xsl:template>
<xsl:template name="main">
<!-- do stuff here -->
</xsl:template>
</xsl:transform>
-----Original Message-----
From: Chris [mailto:phatfish(_at_)gmail(_dot_)com]
Sent: Friday, March 18, 2005 8:39 AM
To: XSL List
Subject: [xsl] Can i use apply-templates to match a xsl:template element?
I would like the output of a xsl:template element to appear in a specific
location in stylesheet. Can i use apply-templates to match the template i
want and have it output there?
eg:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:transform version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html"/>
<xsl:template match="page">
<html>
<head>
</head>
<body>
<div id="header"><xsl:apply-templates
select="header"/></div>
<div id="main"><xsl:apply-templates
select="main"/></div>
</body>
</html>
</xsl:template>
</xsl:transform>
This file will be included into my stylesheets and used as a base layout. I
would like the xsl:template with name="main" to output into the location
above. But im not sure if this is allowed, does select only relate an
element in the source xml document?
I hope you can see what im trying to do, Thanks :)
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