Try
margin-left="{concat(string-length(numbering)-1,'mm')}"
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Sven Waibel [mailto:sven(_dot_)waibel(_at_)imbus(_dot_)de]
Sent: 17 March 2005 10:03
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Recursive?
I have a problem now.
I count numbering to indent it.
I did it this way
margin-left="concat(string-length(numbering)-1,'mm')"
but so i don't get the result.
Sven
Michael Kay wrote:
Processing a recursive data structure should always be done
recursively.
I can't see anything in this requirement that can't be
satisfied by a
completely straightforward set of template rules using the standard
<xsl:apply-templates/> technique at each level to process
the children. If
you're struggling with it, it would be helpful to know where your
difficulties are.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Sven Waibel [mailto:sven(_dot_)waibel(_at_)imbus(_dot_)de]
Sent: 17 March 2005 08:56
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Recursive?
Hi everybody,
my xml:
<?xml version="1.0" encoding="ISO-8859-15"?>
<it>
<tt id="20">
<numbering>1</numbering>
<name><![CDATA[test0]]></name>
<tc id="4611686020000000015">
<numbering>1.1</numbering>
<name><![CDATA[test1]]></name>
</tc>
</tt>
<tt id="21">
<numbering>2</numbering>
<name><![CDATA[test2]]></name>
<tt id="22">
<numbering>2.1</numbering>
<name><![CDATA[test3]]></name>
<tt id="23">
<numbering>2.1.1</numbering>
<name><![CDATA[tgf]]></name>
<tc id="4611686020000000012">
<numbering>2.1.1.1</numbering>
<name><![CDATA[test4]]></name>
</tc>
<tc id="4611686020000000013">
<numbering>2.1.1.2</numbering>
<name><![CDATA[test5]]></name>
</tc>
</tt>
<tc id="4611686020000000014">
<numbering>2.1.2</numbering>
<name><![CDATA[test6]]></name>
</tc>
</tt>
</tt>
</it>
I want to get this:
number name
1 test0
1.1 test1
2 test2
2.1 test3
2.1.1 test4
2.1.1.1 test5
2.1.1.2 test6
2.1.2 test7
Should i do it recursively or is there a better way to achieve it?
Thanks and best regards.
Sven
2.
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