Hi nutdev,
At 01:59 PM 3/9/2005, you wrote:
I have an xsl which is something like this:
<root>
<a><b>lots of stuff</b></a>
<a><b>lots of stuff</b></a>
<a><b>lots of stuff</b></a>
<a><b>lots of stuff</b></a>
<a><b>lots of stuff</b></a>
<a><b>lots of stuff</b></a>
<a><b>lots of stuff</b></a>
</root>
and I have a template
<xsl:template match="a">
<!--Show which element I on using-->
<!--display lots of stuff-->
</xsl:template>
For the <!--Show which element I on using--> I am trying various
different combinations
of <xsl:number value="something">
Take the @value attribute off and see what happens. You do not want to
provide a value to the xsl:number instruction; without it, it will
calculate a value on its own (which is what you want).
Any good XSLT reference book will tell you what the @value, @count, @level
and @format attributes on xsl:number will do, but from your description it
appears you want the default behavior.
I have tried counting preceding siblings, position and several other
things, and I only ever get
a 1.
We'd have to see a little more before we could diagnose why that was happening.
I would be really grateful if you could tell me What is the right way to
show 1,2,3,4,5 and then contents of each 'a´ element within the
template.
D'you know how to apply templates?
<xsl:template match="a">
<xsl:number format="1 "/>
<xsl:apply-templates/>
</xsl:template>
Cheers,
Wendell
======================================================================
Wendell Piez
mailto:wapiez(_at_)mulberrytech(_dot_)com
Mulberry Technologies, Inc. http://www.mulberrytech.com
17 West Jefferson Street Direct Phone: 301/315-9635
Suite 207 Phone: 301/315-9631
Rockville, MD 20850 Fax: 301/315-8285
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Mulberry Technologies: A Consultancy Specializing in SGML and XML
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