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RE: How to select nodes with explicitly set default namespace

2005-03-09 09:56:33
You bind an explicit prefix to the namespace URI in the stylesheet

xmlns:p="namespace"

and use this prefix in the path expression

./p:document

Alternatively in XSLT 2.0 you can define default-xpath-namespace="namespace"
and this then applies to all unprefixed names in path expressions.

Michael Kay
http://www.saxonica.com/

 

-----Original Message-----
From: Olaf Meske [mailto:omeske(_at_)softcare(_dot_)de] 
Sent: 09 March 2005 16:34
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] How to select nodes with explicitly set 
default namespace

Hi,

I don't know how to select a node with the default namespace if this 
namespace is explicitly set in the xml document. If I use any 
other name 
for the namespace something like namespace::document would match the 
elemet <namespace:document> .... </namespace:document>
and if I remove the default namespace definition from the xml 
document 
the match="document" does also work, but if I set the default 
namespace 
it doesn't.
It doesn't match eighter if I use '':document or "":document 
or ::document

Is there any special XPath function I have to use this?
I use Saxon 7.9.1 and XSL 2.0.

Regards,

Olaf Meske


Here are the XML (minitest7.xml)
==============================================================
=========
==============================================================
=========
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<?xml-stylesheet type="text/xsl" href="minitest7.xsl"?>
<document xmlns="http://www.example.com/minitest7";>
      <content>Test text with <b>bold</b> tags.</content>
</document>

==============================================================
=========
==============================================================
=========
and the XSL (minitest7.xsl)
==============================================================
=========
==============================================================
=========
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0"
      xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
      xmlns:xs="http://www.w3.org/2001/XMLSchema";
      xmlns="http://www.example.com/minitest7";
      >

      <xsl:output method="xml" version="1.0" encoding="UTF-8" 
indent="yes"/>

      <xsl:template match="/">
      <root>
              <content><xsl:apply-templates 
select="document"/></content>
      </root>
      
      </xsl:template>

      <xsl:template match="document" >
              <doc x="doc content">
                      <xsl:copy-of select="."/>
              </doc>
      </xsl:template>

</xsl:stylesheet>
==============================================================
=========
==============================================================
=========

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