The top of the tree is a root node (1.0 terminology) or document node (2.0).
This is what "/" refers to. It's not an element: it's the parent of the
outermost element (and any comments and processing instructions that precede
or follow the outermost element). The root node has no name.
The outermost element can be obtained using /*, and its name is name(/*).
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: c p [mailto:bugs75il(_at_)yahoo(_dot_)com]
Sent: 04 March 2005 22:00
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] XML Root Element
Is there a way I can get the name of the root element?
For example, in the following xml:
-------------------------------------------------
<?xml version='1.0' encoding='UTF-8'?>
<?xml-stylesheet type='text/xsl' href='my.xsl'?>
<myxmlroot>
<sometag></sometag>
</myxmlroot>
-------------------------------------------------
Is there a way I can get the string "myxmlroot" which
is the name of my root element?
I have tried doing something like this via my.xsl:
-------------------------------------------------
<?xml version='1.0' encoding='UTF-8'?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<xsl:value-of select="name()"/>
</xsl:template>
</xsl:stylesheet>
-------------------------------------------------
The name() function does not work by putting it in the
"/" template. It prints the documents root (system
root I think?) and not the root element name which is
what I want. How do I get to this?
Thanks,
C
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