Any ideas how I can find out what the position of the current node is in a
foreign node set? (As opposed to the position in the current node set)
Note that sets are unordered data structures, so there isn't really any
notion of position within a nde set. It is xsl:for-each which sorts the
elements in to document order, not an intrinsic property of the node
set. (This changes in xslt2 draft which uses ordered sequences rather
than sets)
If I understand corectly you want to generate your rows with a td for
every item in A and just do something if that item is in B so
<xsl:for-each select="$A">
<td>
<xsl:if test="count($B|.)=count($B)">
<xsl:apply-templates select="."/>
</xsl:if>
</td>
</xsl:for-each>
David
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