I thought I could just do the following:
<xsl:apply-templates select="processing-instruction()" />
But if I do that, the other template never gets applied.
But that's not what your stylesheet does, it does:
<xsl:apply-templates select="processing-instruction" />
(which selects elements called "processing-instruction")
It would also be useful to show us the source document so we can check if
your match pattern actually matches.
Michael Kay
http://www.saxonica.com/
If I change
the line to
<xsl:apply-templates select="node()" />
I get the output that I want, but a lot of other output as well.
I have tried
<xsl:apply-templates
select="processing-instruction('FM')[substring-before(substrin
g-after(.,
'MARKER ['), ']')='Filename']" />
But that doesn't work, either.
Here's the entire stylesheet, just in case it helps.
-----
<?xml version='1.0' ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="text"/>
<xsl:template match="dita">
<xsl:variable name="crossRefId" select="@Id"/>
<xsl:value-of select="$crossRefId"/>
<xsl:apply-templates select="processing-instruction" />
</xsl:template>
<xsl:template
match="processing-instruction('FM')[substring-before(substring
-after(.,'
MARKER ['), ']')='Filename']">
<xsl:variable name="filename" select="substring-after(.,
'[Filename] ')" />
<xsl:value-of select="$filename"/>
</xsl:template>
</xsl:stylesheet>
-----
The $crossRefId variable is set and output, but $filename
isn't output.
Any ideas?
Steve
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