Hi Michael, thank you very much for the reply.
I had a feeling this was the case before, thank you for re-affirming
my supicions. So do you have any advice for pulling this information
out? or is it impossible? I appreciate any thoughts you have on this
matter (unless they have to do with re-writing my entire xml base :)).
Thank you
Spencer
On 4/25/05, Michael Kay <mike(_at_)saxonica(_dot_)com> wrote:
Thanks once again for the reply. I've retested my application and do
not think the URI is the problem. As an example
.
.
.
<xsl:for-each select="part">
<xsl:variable name="filename" select="concat('file:///',
position(), '.htm'"/>
<xsl:result-document href={$filename}" format="html">
<html>
<body>
<!-- Test -->
<xsl:value-of="/act/title"/>
<!--End of Test -->
<xsl:apply-templates mode="content"/>
</body>
</html>
</xsl:result-document>
</xsl:for-each>
</xsl:template>
Now let's say I have 4 parts in an xml document. I do get 5 files in
the end (1 table of contents and 4 parts) and each file is named as
expected and each file picks up the title. However none of the files
pick up any content from the <xsl:apply-templates mode="content"/>.
Your example XML was:
<act>
<part>this is a part we will divide a file on</part>
<section>This is a section</section>
<clause>This is a clause</clause>
<part>This is another part, in the new scheme of things, a second
file</part>
<section>Yet another section</section>
</act>
In this example, the only child of the <part> element is a single text node.
I would expect this text to be output as a result of the
<xsl:apply-templates mode="content"/> call. I would not expect the section
and clause elements to be output, because they are not children of the
<part>.
Michael Kay
http://www.saxonica.com/
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