Hi,
I have moved the xsd:schema inside the variable. But now it
expects me to declare the prefixes for each namespace in the external file.
Cheers,
Omprakash.V
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0"
xmlns:xalan="http://xml.apache.org/xalan"
xmlns:xsd="schema ns"
exclude-result-prefixes="xalan"
>
<xsl:output method="xml" indent="yes" />
<xsl:template match="/">
<xsl:variable name="rtf">
<xsd:schema>
<xsl:for-each select="document('nmspaces')/namespaces/namespace">
<xsl:attribute name="{(_at_)prefix}:foo" namespace="{.}"/>
</xsl:for-each>
</xsd:schema>
</xsl:variable>
<xsl:copy-of select="xalan:nodeset($rtf)/*/namespace::
*"/><xsl:text>,</xsl:text>
</xsl:template>
</xsl:stylesheet>
David
Carlisle To:
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
<davidc(_at_)nag(_dot_)c cc: (bcc:
omprakash.v/Polaris)
o.uk> Subject: Re: [xsl] Trying to build
a schema and add a namespace
04/20/2005
04:51 PM
Please
respond to
xsl-list
<xsd:schema>
<xsl:variable name="rtf">
<xsl:for-each select="document('nmspaces')/namespaces/namespace">
<xsl:attribute na
That should have generate an error you need to have an element to hold
the attribute (and namespace) nodes, you can't just generate them under
the / node of the variable.
<xsl:copy-of select="xalan:nodeset($rtf)/*/namespace::*
That will generate nothing as xalan:nodeset($rtf)/* is the empty set
as there is no element.
David
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