On Tue, Apr 12, 2005 at 09:23:40AM +0530,
omprakash(_dot_)v(_at_)polaris(_dot_)co(_dot_)in wrote:
Hi,
Are you particular about using the ancestor axis bcos I don't think
it is of much use here. You can do this using the descendant axis as
follows:
<xsl:if test="descendant::menu[(_at_)dept = $dept]">
<xsl:value-of select="'node found'"/>
</xsl:if>
This is assuming I understood your requirement right.
Feh.. I misread the question... I was thinking he was
trying to find out whether the current element had a menu
element $depth levels deeper into the document.. :-)
... read problem.. *then* solve problem... not the
reverse.. :-)
-Brian
Cheers,
Omprakash.V
Brian Chrisman
<incubus(_at_)shell To:
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
.izap.com> cc: (bcc: omprakash.v/Polaris)
Subject: Re: [xsl] If Current
Node Is Ancestor!
04/12/2005
09:04 AM
Please respond
to xsl-list
On Tue, Apr 12, 2005 at 01:19:41PM +1000, Adam J Knight wrote:
Hi all,
I am trying to test whether a current node is an ancestor of a menu node
with a dept attribute equal to $depth. I appear to be struggling with
this
conceptually and would appreciate any help!!
<xsl:if test="//menu[(_at_)dept != $dept]/ancestor::menu ">
<xsl:attribute name="class">nav_close</xsl:attribute>
</xsl:if>
Here's one way I *think* you could do it.. but I haven't
tried it.. and I don't use this functionality much..
<xsl:variable name="my-depth" select="count(ancestor::*)"/>
<xsl:if test=".//menu[(count(ancestor::*) - $my-depth) = $depth]">
foo
</xsl:if>
Cheers,
Adam
?
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