Hi,
Here's the xsl that does what you want.
<?xml version="1.0" encoding="ISO8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl
="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" />
<xsl:template match="/">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="article">
<xsl:apply-templates select="bb"/>
</xsl:template>
<xsl:template match="bb">
<xsl:apply-templates select="preceding-sibling::*[self::link][current
()/@id = @id]">
<xsl:with-param name="bbtext" select="."/>
</xsl:apply-templates>
</xsl:template>
<xsl:template match="link">
<xsl:param name="bbtext"/>
<xsl:value-of select="concat(., $bbtext)"/>
</xsl:template>
</xsl:stylesheet>
GPoindexter(_at_)co
mputer.org To:
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
cc: (bcc: omprakash.v/Polaris)
04/08/2005 Subject: [xsl] Attributes:
comparing two attribute values
02:19 AM
Please respond
to xsl-list
If the bb/@id matches the the link/@id then prepend the "right Link info"
to the contents of the bb element.
My problem is I'm not sure of the correct syntac for this test.
Any help would be appreciated.
<article>
<link id="bibT073213">right Link Info</link>
<link id="bibT073211">wrong Link Info</link>
............
<bb id="bibT073212">Mommy Reference Information</bb>
<bb id="bibT073213">Baby Reference Information</bb>
<bb id="bibT073214">Poppa Reference Information</bb>
</article>
Thanks
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