hi david,
thx for reply.
this was the incentive for me to solve it.
---------------------------------->
The current node after $dfile[ is the root node (/) of the document
referenced by $datafile) so the first id used in your concat(id will be the
empty string unless id is the top level element of $datafile, and will be
the whole string content of $datafile if its top level element is id. I
doubt this is what you intended, but can't suggest a fix given teh available
information.
<----------------------------------
The solution was to make a loop which selects the pageid corresponding to
the category-id relation.
<xsl:variable name="dfile" select="document($datafile)"/> <xsl:key
name="pagename" match="siteinfo/pages/page" use="name"/>
<xsl:for-each
select="document($categoryfile)//categories/category[visible!='off' and
id!=0 and member='off']">
<xsl:variable name="catname" select="catname"/>
<xsl:variable name="catid" select="id"/>
<xsl:variable name="pagename" select="$dfile[key('pagename',
$catname)]"/>
<xsl:variable name="pageid">
<xsl:for-each
select="document($datafile)//siteinfo/pages/page[category=$catid]">
<xsl:variable name="pid" select="id"/>
<xsl:value-of select="id"/>
</xsl:for-each>
</xsl:variable>
<xsl:choose>
<!-- the 'test=' expression converts the returned nodeset of
xsl:key to a boolean value, therefore it can be requested for true() or
false() -->
<xsl:when test="$pagename">
,"<xsl:value-of select="$nbsp"/><xsl:value-of
select="$not"/><xsl:value-of select="$nbsp"/><xsl:value-of
select="$catname"/>","default.asp?id=<xsl:value-of
select="$pageid"/>&mnu=<xsl:value-of
select="$pageid"/>","","<xsl:value-of select="$catname"/>",0
</xsl:when>
<xsl:otherwise>
,"<xsl:value-of select="$nbsp"/><xsl:value-of
select="$not"/><xsl:value-of select="$nbsp"/><xsl:value-of
select="$catname"/><xsl:value-of
select="$nbsp"/>","show-menu=<xsl:value-of select="$catname"/>",,"",1
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
regards,
christian schlemmer
Codeworx <<
Vorstadt 17a
A-6800 Feldkirch
T +43 664 3044577
F +43 5522 84280
E studio(_at_)codeworx(_dot_)info
I www.codeworx.info
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