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Re: generating namespace attributes in result

2005-04-07 07:30:26

        Iam using <xsl:for-each select="namespace:*"> to iterate over all
namespace attributes on the input element 

namespace decarations are not attributes to xpath.
The above doesn't just iterate over any explict xmlns=... that appear in
the source but rather it iterates over all namespace nodes, that are on
that element which includes any namespaces declared on any ancestor
element.


  <xsl:attribute name="$attrname">
  <xsl:value-of select=$attrval"/>
  </xsl:attribute>

You can not generate namespace nodes with xsl:attribute. In XSLT2 you
could use xsl:namespace to generate namespace nodes but in XSLT1 you
have to copy then from the source or generate elements or attributes in
the correct namespace using xsl:element.

So for example if your source is

<xxx>
 <name>zzz</zzz>
 <ns>http://www.example.com</ns>
</xx>

and you want to generate
<zzz xmlns="http://www.example.com"/>

Then you want to do

<xsl:template match="xxx">
 <xsl:element name="{name}" namespace="{ns}"/>
</xsl:template>

Hope this is clear.

The FAQ has more examples of generating namespace nodes.

David

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